## Math Quiz

When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are

$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$

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Question 1 |

**What is the square root of 2.**

$\sqrt{2}$ | |

$\sqrt{b^2}$ | |

$2$ | |

$3\sqrt{2}$ | |

$\frac{1}{3}$ | |

$y^3$ |

Question 1 Explanation:

This is the $\sqrt{2}$.

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$\sqrt{a^2+b^2}$

$3\times4$